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5.20(a). A compass needle free to turn in a horizontal plane is placed at the centre of circular coil of 30 turns and radius 12 cm. The coil is in a vertical plane making an angle of with the magnetic meridian. When the current in the coil is 0.35 A, the needle points west to east. Determine the horizontal component of the earth’s magnetic field at the location.
Answers (1)
Given,
Number of turns in the coil, n = 30
Radius of coil, r = 12cm = 0.12m
Current in the coil, I = 0.35A
The angle of dip, = 45o
We know, Magnetic fields due to current carrying coils, B =
Now, Horizontal component of the earth’s magnetic field = Bsin
(Hint: Take sin45o as 0.7)
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