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3.(iii)      A die is thrown, find the probability of following events:

              (iii) A number less than or equal to one will appear
 

Answers (1)

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Sample space when a die is thrown, S = {1,2,3,4,5,6}

\therefore Number of possible outcomes n(S) = 6

Let E be the event of getting a number less than or equal to one = {1}

\therefore n(E) = 1

\therefore P(E) = \frac{n(E)}{n(S)}  = \frac{1}{6} 

= 0.167

Posted by

HARSH KANKARIA

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