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3.(v)      A die is thrown, find the probability of following events:

               (v) A number less than \small 6 will appear.

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Sample space when a die is thrown, S = {1,2,3,4,5,6}

\therefore Number of possible outcomes n(S) = 6

Let E be the event of getting a number less than 6 will appear = {1,2,3,4,5} 

\therefore n(E) = 5

\therefore P(E) = \frac{n(E)}{n(S)}  = \frac{5}{6} 

= 0.83

Posted by

HARSH KANKARIA

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