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13.(iii)   A die is thrown once. Find the probability of getting an odd number.

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Possible outcomes when a die is thrown = {1,2,3,4,5,6}

Number of possible outcomes once = 6

(iii) Let O be the event of getting an odd number.

Odd numbers on the die are = {1,3,5}

Number of favourable outcomes = 3

\therefore P(O) = \frac{favourable\ outcomes}{total\ outcomes} = \frac{3}{6}

= \frac{1}{2}

Therefore, the probability of getting an odd number is  \frac{1}{2}

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HARSH KANKARIA

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