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A lot of 100 watches is known to have 10 defective watches. If 8 watches are selected (one by one with replacement) at random, what is the probability that there will be at least one defective watch?

Answers (1)

Given-

There are 10 defective watches in 100 watches

The probability of defective watch from a lot of 100 watch =\frac{10}{100}=\frac{1}{10}$ 

P=\frac{1}{10},q=\frac{9}{10}, n=8$ and $r \geq 1$
As we know that

\\\mathrm{P}(\mathrm{X})=^\mathrm{n}{\mathrm{c}_{\mathrm{r}}}(\mathrm{p})^{\mathrm{r}} \mathrm{q}^{\mathrm{n}-\mathrm{r}}$ \\$\therefore \mathrm{P}=(\mathrm{r} \geq 1)=1-\mathrm{P}(\mathrm{r}=0)$ \\$=1-^8{c_{0}}\left(\frac{1}{10}\right)^{0}\left(\frac{9}{10}\right)^{8-0}$ \\$=1-\frac{8 !}{0 ! 8 !} \times\left(\frac{9}{10}\right)^{8}$ \\$=1-\left(\frac{9}{10}\right)^{8}$

Posted by

infoexpert22

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