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Q5.13 A man of mass 70 kg stands on a weighing scale in a lift which is moving

(c) upwards with a uniform acceleration of 5 ms^{-2} . What would be the readings on the scale in each case?

Answers (1)

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(c) The acceleration of lift is given to be 5 m/s2. Let us assume the upward direction to be positive.

       Using Newton's law of motion, we can write :

                                             R\ -\ mg\ =\ ma

or                                          R\ -\ 70(10)\ =\ 70(5)

or                                          R\ =\ 350 +\ 700\ =\ 1050\ N

Thus the reading of the weighing scale will be :

                                                                               =\ \frac{R}{g}\ =\ \frac{1050}{10}\ =\ 105\ Kg

Posted by

Devendra Khairwa

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