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23. (a) A uniform magnetic field of 1.5 T exists in a cylindrical region of radius 10.0 cm, its direction parallel to the axis along east to west. A wire carrying current of 7.0 A in the north-to-south direction passes through this region. What is the magnitude and direction of the force on the wire if the wire intersects the axis?

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The length of wire inside the magnetic field is equal to the diameter of the cylindrical region: 20.0 cm = 0.2 m.

Magnetic field strength = 1.5 T.

Current flowing through the wire: 7.0 A

The angle between the direction of the current and magnetic field is 90°.

Force on a wire in a magnetic field is calculated by relation,

\\F=BIlsin\theta \\ F=1.5\times 7\times 0.2

F=2.1 N

This force, due to the magnetic field inside the cylindrical region, acts on the wire in a vertically downward direction.

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