Get Answers to all your Questions

header-bg qa

Q.14.        Compare the power used in the 2\Omega resistor in each of the following circuits:

                (i) a 6 V battery in series with 1\Omega and 2\Omega  resistors

                (ii) a 4 V battery in parallel with 12\Omega and 2\Omega resistors.

               

Answers (1)

best_answer

i) Given : V=6V 

        R=1+2=3Ohm

I=\frac{V}{R}=\frac{6}{3}=2A

In , series current is constant .

So , power =P

P=I^2R=2^2\times 2=8W

ii)Given : V=6V , R=2 Ohm

In ,parallel  combination voltage in the circuit  is constant .

So , power =P

P=\frac{V^2}{R}=\frac{4^2}{2}=8W

Posted by

seema garhwal

View full answer