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  • Density of a gas is found to be 5.46 g/dm^3 at 27 °C at 2 bar pressure. What will be its density at STP?

5.9     Density of a gas is found to be 5.46 \: g/dm^{3}at 27^{o}C at 2 bar pressure. What will be its density at STP ?

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Given the density of a gas is equal to 5.46g/dm^3 at 27^{\circ}C and at 2bar pressure.

Density d = \frac{PM}{RT}, for the same gas at different temperatures and pressures we can apply,

\frac{d_{1}}{d_{2}} = \frac{P_{1}}{T_{1}}\times\frac{T_{2}}{P_{2}}.

Here, d_{1} =5.46g\ dm^_{-3} , T_{1} =27^{\circ}C =300K, P_{1} =2bar.

then at STP, we have d_{2},\ T_{2} = 0^{\circ}C =273K,\ P_{2} =1bar.

\therefore \frac{5.46g\ dm^{-3}}{d_{2}} = \frac{2bar}{300K}\times\frac{273K}{1bar}    or    d_{2} = 3g\ dm^{-3}

Posted by

Divya Prakash Singh

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