Get Answers to all your Questions

header-bg qa

Q7.11     Figure shows a series LCR circuit connected to a variable frequency 230\: V source.  L=5.0HC=80\mu F, R=40\Omega.

(a)    Determine the source frequency which drives the circuit in resonance.

        

Answers (1)

best_answer

Given,

Variable frequency supply voltage V = 230V

Inductance L=5.0H

Capacitance C=80\mu F=80*10^{-6}F

Resistance R=40\Omega

a) Resonance angular frequency in this circuit is given by :

w_{resonance}=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{5*80*10^{-6}}}=\frac{1000}{20}=50rad/sec

Hence this circuit will be in resonance when supply frequency is 50 rad/sec.

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads