Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Find the equation of the circle with centre ( - a, - b) and radius root of a to the power 2 - b to the power 2

5. Find the equation of the circle with

       centre (-a,-b) and radius \sqrt{a^2 - b^2}

Answers (1)

best_answer

As we know, 

The equation of the circle with centre ( h, k) and radius r is given by ;

(x-h)^2+(y-k)^2=r^2

So Given Here

(h,k)=(-a,-b) 

AND r=\sqrt{a^2-b^2}

So the equation of the circle is:

, (x-(-a))^2+(y-(-b))^2=(\sqrt{a^2-b^2})^2

x^2+2ax+a^2+y^2+2by+b^2=a^2-b^2

x^2+y^2+2ax+2by+2b^2=0

Posted by

Pankaj Sanodiya

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years

Latest Question