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Find the equation of the line which satisfy the given conditions:

Q : 8         Perpendicular distance from the origin is 5 units and the angle made by the  perpendicular with the positive x-axis is  30^{\circ}

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 It is given that length of perpendicular is 5 units  and  angle made by the  perpendicular with the positive x-axis is  30^{\circ}
Therefore, equation of line is
x\cos \theta + y \sin \theta = p
In this case p = 5 and  \theta = 30\degree
x\cos 30\degree + y \sin 30\degree = 5\\ x.\frac{\sqrt3}{2}+\frac{y}{2}= 5\\ \sqrt3x+y =10
Therefore, equation of the line  is   \sqrt3x+y =10

Posted by

Gautam harsolia

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