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  • Find the values of k for which the line (k–3) x – (4 – k^2) y + k^2 –7k + 6 = 0 is (c) Passing through the origin.

Q : 1     Find the values of k for which the line                                                                                                 (k-3)x-(4-k^2)y+k^2-7k+6=0  is 

               (c) Passing through the origin.

Answers (1)

best_answer

Given equation of line is 
(k-3)x-(4-k^2)y+k^2-7k+6=0
It is given that it passes through origin (0,0)
Therefore,
(k-3).0-(4-k^2).0+k^2-7k+6=0
k^2-7k+6=0
k^2-6k-k+6=0
(k-6)(k-1)=0
k = 6 \ or \ 1
Therefore, value of k is 6 \ or \ 1

Posted by

Gautam harsolia

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