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Q.5.    From a committee of 8 persons, in how many ways can we choose a chairman

           and a vice chairman assuming one person cannot hold more than one position?
                                                                                                                                                                                                                                                      

Answers (1)

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 From a committee of 8 persons, chairman and a vice chairman are to be chosen assuming one person can not hold more than one position.

Therefore,number of ways of choosing a chairman and a vice chairman is permutations of 8 different objects taken 2 at a time.

Therefore, required number of ways =^{8}P_2

                                                           =\frac{8!}{(8-2)!}

                                                             =\frac{8!}{6!}

                                                              =\frac{ 8\times 7\times 6!}{6!}

                                                               =8\times 7=56

Posted by

seema garhwal

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