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If possible, find the sum of the matrices A and B, where

\begin{array}{l} A=\left[\begin{array}{ll} \sqrt{3} & 1 \\ 2 & 3 \end{array}\right] \\ B=\left[\begin{array}{lll} x & y & z \\ a & b & 6 \end{array}\right] \end{array}

Answers (1)

According to the convention, the number of rows and columns in a matrix is called its order or dimension and the rows of the matrix are listed first and then the columns are listed.

We know that,

For adding or subtracting any two matrices, the need to be of the same order

That is,

If we need to add matrix A and B, then the order of matrix A is m x n then the order of matrix B should be m x n

We have matrices A and B, where

\begin{array}{l} A=\left[\begin{array}{ll} \sqrt{3} & 1 \\ 2 & 3 \end{array}\right] \\ B=\left[\begin{array}{lll} x & y & z \\ a & b & 6 \end{array}\right] \end{array}

We know what order of matrix is,

If a matrix has M rows and N columns, then the matrix has the order M $ \times $ N.

In matrix A:

Number of rows = 2

$ \Rightarrow $ M = 2

Number of column = 2

$ \Rightarrow $  N = 2

Then, order of matrix A = M $ \times $ N

$ \Rightarrow $  Order of matrix A = 2 $ \times $ 2

In matrix B:

Number of rows = 2

$ \Rightarrow $  M = 2

Number of columns = 3

$ \Rightarrow $ M = 3

Then, order of matrix B = M $ \times $ N

$ \Rightarrow $  order of matrix B = 2 $ \times $ 3

Since,

Order of matrix A $ \neq $  Order of matrix B

$ \Rightarrow $  Matrices A and B cannot be added.

Therefore, matrix A and matrix B cannot be added.

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