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Q 9.14 (b) If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48 \times 106m, and the radius of the lunar orbit is 3.8 \times 108m.

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Given,

The radius of the lunar orbit,r =  3.8 \times 108m.

The diameter of the moon,d =  3.48 \times 106m

focal length f = 15m

let  d_1  be the diameter of the image of the moon which is formed by the objective lens.

Now,

the angle subtended by diameter of the moon will be equal to the angle subtended by the image,

\frac{d}{r}=\frac{d_1}{f}

\frac{3.48*10^6}{3.8*10^8}=\frac{d_1}{15}

d_1=13.74 cm

Hence the required diameter is 13.74cm.

Posted by

Pankaj Sanodiya

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