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Q1   In Fig. 6.17, (i) and (ii), DE || BC. Find EC in (i) and AD in (ii).  

        

Answers (1)

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(i) 

 

Let EC be x 

Given: DE || BC

By using the proportinality theorem, we get

     \frac{AD}{DB}=\frac{AE}{EC}

\Rightarrow \frac{1.5}{3}=\frac{1}{x}

\Rightarrow x=\frac{3}{1.5}=2\, cm

\therefore EC=2\, cm

 

(ii) 

 

Let AD be x 

Given: DE || BC

By using the proportinality theorem, we get

     \frac{AD}{DB}=\frac{AE}{EC}

\Rightarrow \frac{x}{7.2}=\frac{1.8}{5.4}

\Rightarrow x=\frac{7.2}{3}=2.4\, cm

\therefore AD=2.4\, cm

 

 

 

 

 

 

 

 

 

 

 

Posted by

seema garhwal

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