Get Answers to all your Questions

header-bg qa

Q.14     Probability of solving specific problem independently by A and B are \frac{1}{2}  and \frac{1}{3} respectively. If both try to solve the problem independently, find the probability that

                (ii) exactly one of them solves the problem

Answers (1)

best_answer

  P(A)=\frac{1}{2}           and        P(B)=\frac{1}{3}

P(A')=1-P(A),      P(B')=1-P(B)

 P(A')=1-\frac{1}{2}=\frac{1}{2}  ,           P(B')=1-\frac{1}{3}=\frac{2}{3}

   probability that exactly one of them solves the problem =P(A\cap B') + P(A'\cap B)

    probability that exactly one of them solves the problem  =P(A).P(B')+P(A')P(B)

                                                                                              =\frac{1}{2}\times \frac{2}{3}+\frac{1}{2}\times \frac{1}{3}

                                                                                              = \frac{2}{6}+\frac{1}{6}

                                                                                            = \frac{3}{6}=\frac{1}{2}

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads