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  • Refer to Question 74 above. The probability that exactly two of the three balls were red, the first ball being red, is A. 1/3 B. 4/7 C. 15/28 D. 5/28

Refer to Question 74 above. The probability that exactly two of the three balls were red, the first ball being red, is
A. 1/3
B. 4/7
C. 15/28
D. 5/28

Answers (1)

Given-

A bag contains 5 red and 3 blue balls

Therefore, Total Balls in a Bag = 8

For exactly 1 red ball probability should be
3 Balls are drawn randomly then possibility for getting 1 red ball
P(E)=P(R).P(B)+P(B).P(R)

\\ \mathrm{P}(\mathrm{E})=\frac{4}{7} \times \frac{3}{6}+\frac{3}{6} \times \frac{4}{7} \\ \text { Hence, } \mathrm{P}(\mathrm{E})=4 / 7

Option B is correct.

Posted by

infoexpert22

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