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Solve each of the following equations: 

Q : 7        \sqrt{2}x^2+x+\sqrt{2}=0

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Given equation is
\sqrt{2}x^2+x+\sqrt{2}=0 
Now, we know that the roots of the quadratic equation is given by the formula
\frac{-b\pm \sqrt{b^2-4ac}}{2a}
In this case the value of a = \sqrt 2 , b =1 \ and \ c = \sqrt2
Therefore,
\frac{-1\pm \sqrt{1^2-4.\sqrt2.\sqrt2}}{2.\sqrt2}= \frac{-1\pm\sqrt{1-8}}{2\sqrt2} = \frac{-1\pm\sqrt{-7}}{2\sqrt2}=\frac{-1\pm\sqrt{7}i}{2\sqrt2}
Therefore, the solutions of the equation are   \frac{-1\pm\sqrt{7}i}{2\sqrt2}

Posted by

Gautam harsolia

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