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Solve each of the following equations: 

Q : 9        x^2+x+\frac{1}{\sqrt{2}}=0

Answers (1)

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Given equation is
x^2+x+\frac{1}{\sqrt{2}}=0 
Now, we know that the roots of the quadratic equation is given by the formula
\frac{-b\pm \sqrt{b^2-4ac}}{2a}
In this case the value of a = 1 , b =1 \ and \ c= \frac{1}{\sqrt2}
Therefore,
\frac{-1\pm \sqrt{1^2-4.1.\frac{1}{\sqrt2}}}{2.1}= \frac{-1\pm\sqrt{1-2\sqrt2}}{2} = \frac{-1\pm\sqrt{-(2\sqrt2-1)}}{2}=\frac{-1\pm\sqrt{(2\sqrt2-1)}i}{2}
Therefore, the solutions of the equation are

   \frac{-1\pm\sqrt{(2\sqrt2-1)}i}{2}

Posted by

Gautam harsolia

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