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Solve the following equation and check your result.

Q.5    2x – 1 = 14 – x

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We have 

                       2x - 1 = 14 - x

Transposing -x to the LHS and -1 to the RHS

                       2x + x = 14 + 1

or                        3x = 15 

Dividing both sides by 3, we get 

                       x = 5 

Check :-  Put x = 5 in both the LHS and the RHS

                 LHS :-     2x - 1 = 2(5) - 1 = 10 - 1 = 9

                 RHS :-     14 - x = 14 - 5 = 9

Hence,                LHS = RHS

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Divya Prakash Singh

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