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Q.7 

              x =\frac{4}{5}\times \left ( x+10 \right )                                         

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We have 

                          x = \frac{4}{5}\left ( x + 10 \right )

                               = \frac{4}{5}x + 8

Transposing   \frac{4}{5}x   to the left-hand side:

                            x - \frac{4}{5}x = 8

or                         \frac{5x-4x}{5} = 8

or                                \frac{x}{5} = 8

Multiplying both sides by 5

                              x = 40

Check :-  Put x = 40 in both the LHS and the RHS.

               LHS :-     x = 40

               RHS :-     \frac{4}{5}\left ( x + 10 \right ) = \frac{4}{5}\left ( 40 + 10 \right )

                                                      = \frac{4}{5}\left ( 50 \right ) = 40

Thus,      LHS = RHS    

      

Posted by

Divya Prakash Singh

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