Get Answers to all your Questions

header-bg qa

Solve the following system of inequalities graphically:

    Q12.    x -2y \leq 3, 3x + 4y \geq 12, x \geq 0, y\geq 1

Answers (1)

best_answer

x -2y \leq 3, 3x + 4y \geq 12, x \geq 0, y\geq 1

Graphical representation of  x-2y=3 \, \, ,3x+4y=12\, \, \, ,x=0\, \, and\, \, y=1  is given in graph below.

For x -2y \leq 3 ,

The  solution to this inequality is region above the  line (x-2y=3) including points on this line because  points on line also satisfy the inequality.

 For 3x + 4y \geq 12,

The  solution to this inequality is region above the line (3x+4y=12)  including points on this line because  points on line also satisfy the inequality.

For \ x \geq 0,

The  solution to this inequality is region right hand side of the line (x=0) including points on this line because  points on line also satisfy the inequality.

For \ y \geq 1,

The  solution to this inequality is region above  the line (y=1) including points on this line because  points on line also satisfy the inequality.

 

Hence, solution to these linear inequalities is shaded region as shown in figure including points on the respective lines.

This can be represented as follows: 

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads