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The annual rainfall record of a city for 66 days is given in the following table.

Rainfall (in cm) 0-10 10-20 20-30 30-40 40-50 50-60
Number of days 22 10 8 15 5 6

Calculate the median rainfall using ogives (of more than type and of less than type)

Answers (1)

Answer. [20]
Solution.

(i) less than type (ii) more than type
Rain fall No.of days Rain fall Number of days
less than 0 0 more than or equal to 0 66
less than 10 0+22 = 22 more than or equal to 10 66-22 = 44
less than 20 22+10 = 32 more than or equal to 20 44-10 = 34
less than 30 32+8 = 40 more than or equal to 30 34-8 = 26
less than 40 40+15 = 55 more than or equal to 40 26-15 = 11
less than 50 55+5 =60 more than or equal to 50 11 - 5 =6
less than 60 60+6 =66 more than or equal to 60 6-6 =0

Now let us draw ogives of more than type and of less than type then find the median

N= 66,\frac{N}{2}= \frac{66}{2}= 33

Here median is 20

 

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