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  • The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei -41 ^20 Ca from the following data:

Q.13.24 (i) The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei _{20}^{41}\textrm{Ca} from the following data:

                    m(_{20}^{40}\textrm{Ca})=39.962591\; u

                    m(_{20}^{41}\textrm{Ca})=40.962278 \; u

                    m(_{13}^{26}\textrm{Al})=25.986895 \; u

                     m(_{13}^{27}\textrm{Al})=26.981541 \; u

Answers (1)

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The reaction showing the neutron separation is

_{20}^{41}\textrm{Ca}+E\rightarrow _{20}^{40}\textrm{Ca}+_{0}^{1}\textrm{n}

\\E=(m(_{20}^{40}\textrm{Ca})+m(_{0}^{1}\textrm{n})-m(_{20}^{41}\textrm{Ca}))c^{2}\\ E=(39.962591+1.008665-40.962278)c^{2}\\ E=(0.008978)u\times c^{2}

But 1u=931.5 MeV/c2

Therefore E=(0.008978)\times931.5

E=8.363007 MeV

Therefore to remove a neutron from the _{20}^{41}\textrm{Ca} nucleus 8.363007 MeV of energy is required 

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