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  • The probability that a non leap year selected at random will contain 53 Sundays is (A) 1 by 7 (B) 2 by 7 (C) 3 by 7 (D) 5 by 7

The probability that a non leap year selected at random will contain 53 Sundays is
(A) \frac{1}{7}                    (B) \frac{2}{7}                     (C) \frac{3}{7}                     (D) \frac{5}{7}

Answers (1)

Answer.    [A]
Solution. Probability: probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.
In 365 days there are 52 weeks and 1 day.
If it contain 53 sunday then the 1 day of the year must be sunday.
But there are total 7 days.
Hence total number of favorable cases = 1
Hence probability of 53 sunday = \frac{Number\, of\, favourable\, cases}{Total\, cases}

                                                   = \frac{1}{7}          

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infoexpert27

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