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Q : 11.9 The work function for a certain metal is 4.2\hspace{2mm}eV. Will this metal give photoelectric emission for incident radiation of wavelength 330\hspace{1mm}nm

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The energy of photons having 330 nm is

\\E=\frac{hc}{\lambda } \\ E=\frac{6.62\times 10^{-34}\times 3\times 10^{8}}{330\times 10^{-9}\times 1.6\times 10^{-19}}\\ E=3.7\ eV

Since this is less than the work function of the metal there will be no photoelectric emission.

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