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Get Answers to all your Questions
8. (iv) Three coins are tossed once. Find the probability of getting
(iv) at most heads
Answers (1)
Sample space when three coins are tossed: [Same as a coin tossed thrice!]
S = {HHH, HHT, HTH, HTT, THH, TTH, THT, TTT}
Number of possible outcomes, n(S) = 8 [Note: 2x2x2 = 8]
Let E be the event of getting at most 2 heads = Event of getting 2 or fewer heads = {HHT, HTH, THH, TTH, HTT, THT}
n(E) = 6
The required probability of getting almost 2 heads is .
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