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13.7   Two coins are tossed once, where

            (i) E : tail appears on one coin, F : one coin shows head

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E : tail appears on one coin, F : one coin shows head

Total outcomes =4 

E=\left \{ HT,TH \right \}=2

F=\left \{ HT,TH \right \}=2

E\cap F=\left \{ HT,TH \right \}=2

P(F)=\frac{2}{4}=\frac{1}{2}

P(E\cap F)=\frac{2}{4}=\frac{1}{2}

P(E| F)=\frac{P(E\cap F)}{P(F)}

P(E| F)=\frac{\frac{1}{2}}{\frac{1}{2}}

P(E| F)=1

Posted by

seema garhwal

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