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1. We know that parallelogram is also a quadrilateral. Let us also split such a quadrilateral into two triangles, find their areas  and hence that of the parallelogram. Does this agree with the formula that you know already? (Fig 11.12)

 

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Area \:of \:quadrilateral \:ABCD = Area \:of( \bigtriangleup ABD \:+\:\bigtriangleup BCD)

                                                           =\left ( \frac{1}{2}\times b\times h \right )+\left ( \frac{1}{2}\times b\times h \right )                                     

                                                            =bh

This agree with the formula that we know already.

 

Posted by

seema garhwal

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