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Get Answers to all your Questions
6. Write a digit in the blank space of each of the following numbers so that the number formed is divisible by 11 :
(a) 92 __ 389 (b) 8 __ 9484.
Answers (5)
(a) 92 __ 389
Sum of odd digits = 9 + (blank space) + 8 = 17 + blank space
Sum of even digits = 2 + 3 + 9 = 14
As we know,
The number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is divisible by 11.
If we make the sum of odd digits = 25
then we will have difference = 25 - 14 = 11
which is divisible by 11.
To make the sum of odd digits = 25,
the number at black space would be 8.
(b) 8 __ 9484
Sum of odd digits = 8 + 9 + 8 = 25
Sum of even digits = blank space + 4 + 4 = blank space + 8
The number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is divisible by 11.
If we make the sum of even digits = 14 then we will have difference = 25 - 14 = 11 which is divisible by 11.
To make the sum of even digits = 14,
the number at black space would be 6.
(A)
Sum of odd places are =9+X+8=17+X
Sum of even places are=2+3+9=14
Difference=17+X-14
=3+X
3+X=0
X=-3
Since,(-3)is negative number
So,we cannot take it
Since 11 is the nearest multiple of 11
3+X=11
X=11-3
X=8
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