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Which of the following is an anionic detergent?
Option: 1 Sodium stearate
Option: 2 Sodium lauryl sulphate
Option: 3 Cetyltrimethyl ammonium bromide
Option: 4 Glyceryl oleate

As we have learned

Phenol formation from Benzenesulphonic acid -

Acidification of sodium salt gives phenol.

- wherein

C_{6}H_{5}SO_{3}Na+NaOH\xrightarrow[HCl]{fuse}C_{6}H_{5}-OH+Na_{2}SO_{3}

 

 

 Sodium lauryl sulphate has anionic charge 

 

 

 

 

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Posted by

Ritika Jonwal

The correct sequence of reagents for the following conversion will be :
Option: 1 CH_{3}MgBr, \; \left [ Ag\left ( NH_{3} \right )_{2} \right ]^{+}OH^{-} , H^{+}/CH_{3}OH  

Option: 3 \left [ Ag\left ( NH_{3} \right )_{2} \right ]^{+}OH^{-},   CH_{3}MgBr,    H^{+}/CH_{3}OH

Option: 5 \left [ Ag\left ( NH_{3} \right )_{2} \right ]^{+}OH^{-},  H^{+}/CH_{3}OH , CH_{3}MgBr,

Option: 7 CH_{3}MgBr,  H^{+}/CH_{3}OH\left [ Ag\left ( NH_{3} \right )_{2} \right ]^{+}OH^{-},
 

?

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Posted by

vishal kumar

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Which of the following compounds will show highest dipole moment ?         
Option: 1  (I)
Option: 2 (II)
Option: 3 (III)
Option: 4 (IV)
 

As we discussed in concept

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Posted by

vishal kumar

For the following reactions: where k_{s} and k_{e} are respectively, the rate constants for substitution and elimination, and \mu = \frac{k_{s}}{k_{e}}, the correct option is ___________.
Option: 1 \mu _{A}>\mu _{B}and k_{e}(A)>k_{e}(B)
Option: 2 \mu_{B}>\mu _{A}and k_{e}(A)>k_{e}(B)
Option: 3 \mu_{A}>\mu_{B}and k_{e}(B)>k_{e}(A)
Option: 4 \mu_{B}>\mu_{A}and k_{e}(B)>k_{e}(A)
 

 

This is williamson synthesis.

 

Substitution is better for prrimary Z means A and Elimination tertiary or secondary Z means B.

\mathrm{k_e(B)>k_e(A)} will come.

Now, \mathrm{\mu = \frac{k_s}{k_e}}

A favours substitution and B favour elimination.
So, for A,  ks  will be greater  than ke.

then  \mathrm{\mu_A > \mu_B} will right.

Therefore, Option(3) is correct.

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Posted by

Ritika Jonwal

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What is the correct IUPAC name of the given compound ?
Option: 1 2,2-Dimethylbutanoic acid 
Option: 2 2-Carboxyl-2-methylbutane 
Option: 3 2-Ethyl-2-methylpropanoic acid 
Option: 4 3-Methylbutane carboxylic acid

 IUPAC name of the compound:

2,2-Dimethylbutanoic acid 

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Posted by

Safeer PP

If 10\; mL of H_{2}SO_{4} is mixed with 10\; mL  of Mg(OH)_{2} of the same concentration, the resultant solution will give the following colour with universal indicator :
Option: 1 Red
Option: 2 Yellow
Option: 3 Green
Option: 4 Blue

Green

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Posted by

Safeer PP

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An aqueous solution ‘A’ turns phenolphthalein solution pink. On addition of an aqueous solution ‘B’ to ‘A’, the pink colour disappears. The following statement is true for solution ‘A’ and ‘B’.
 
Option: 1 A is strongly basic and B is a weak base.
 
Option: 2 A is strongly acidic and B is a weak acid.
 
Option: 3 A has pH greater than 7 and B has pH less than 7.
 
Option: 4 A has pH less than 7 and B has pH greater than 7.

An aqueous solution ‘A’ turns phenolphthalein solution pink. On the addition of an aqueous solution ‘B’ to ‘A’, the pink color disappears. According to the statement, 
A has pH greater than 7 and B has pH less than 7.

Hence option C is correct 

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Posted by

Safeer PP

When a small amount of acid is added to water, the phenomena which occur are: (A)    Dilution
(B)    Neutralisation
(C)    Formation of H3O+ ions
(D)    Salt formation The correct statemant is :
Option: 1 (A and (C)
Option: 2 (B) and (D)
Option: 3 (A) and (D)
Option: 4 (C) and (D)

When a small amount of acid is added to water, the phenomena which occur are:

(A)    Dilution
(C)    Formation of H3O+ ions
 

The correct statemants are A and C. 

Therefore option A is correct 

 

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Posted by

Safeer PP

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A visually challenged student, has to perform a lab test to detect the presence of acid in a given solution. The acid-base indicator prefferred by him will be :
Option: 1 Blue litmus
Option: 2 Clove oil
Option: 3 Red cabbage extract
Option: 4 Hibiscus extract

 The acid-base indicator prefferred by him will be Clove oil 

Hence option B is correct 

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Posted by

Safeer PP

When sodium hydrogen carbonate is added to ethanoic acid a gas evolves.
Consider the following statements about the gas evolved ? (A)    It turns lime water milky.
(B)    It is evolved with a brisk effervescence.
(C)    It has a smell of burning sulphur.
(D)    It is also a by - product of respiration. The correct statements are:
Option: 1 (A) and (B) only
Option: 2 (B) and (D) only
Option: 3 (A), (C) and (D)
Option: 4 (A), (B) and (D)

When sodium hydrogen carbonate is added to ethanoic acid a gas evolves which is Carbon dioxide. 

(A)    It turns lime water milky.
(B)    It is evolved with a brisk effervescence.
(D)    It is also a by - product of respiration.

(A), (B) and (D) are correct options. 

Hence option D is correct 

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Posted by

Safeer PP

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