A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s . If the catching process is completed in 0.1 s the force of the blow exerted by the ball on the hand of the player is equal to
300 N
150 N
3 N
30 N
30 N
View Full Answer(2)A uniform cylinder of length L and mass M having cross - sectional area A is suspended, with its length vertical,from a fixed point by a massless spring,such that it is half submerged in a liquid of density at equilibrium position. The extension of the spring when it is in equilibrium is :
(Here is spring constant)
(Here is spring constant)
(Here is spring constant)
(Here is spring constant)
As we have learned @2013
At equilibrium
Option 1)
(Here is spring constant)
Option 2)
(Here is spring constant)
Option 3)
(Here is spring constant)
Option 4)
(Here is spring constant)
View Full Answer(1)A heavy box is to be dragged along a rough horizontal floor. To do so, person A pushes it at an angle 300 from the horizontal and requires a minimum force FA, while person B pulls the box at an angle 600 from the horizontal and needs minimum force FB.If the coefficient of friction between the box and the floor is the ratio is
As learnt (Concept missing)
Given 1: person pushes box
Fa cos 30= (mg+Fa sin 30)M
-------------- (1)
Case 2. Person pulls box
------------------- (2)
Option 1)
This option is incorrect
Option 2)
This option is incorrect
Option 3)
This option is incorrect
Option 4)
This option is correct
View Full Answer(1)Three masses m, 2m and 3m are moving in x-y plane with speed 3u, 2u, and u respectively as shown in figure. The three masses collide at the same point at P and stick together. The velocity of resulting mass will be :
As we learnt in
Law of Consevation of Momentum -
then
- wherein
Independent of frame of reference
Pi = Py
Option 1)
Incorrect
Option 2)
Incorrect
Option 3)
Incorrect
Option 4)
Correct
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A small ball of mass m starts at a point A . with speed vo and moves along a frictionless track AB as shown. The track BC has coefficient of friction . The ball comes to stop at C after travelling a distance L which is :
As we learnt in
Impulse Momentum Theorem -
- wherein
If is increased, average force is decreased
Apply convervation of Energy
Let a be the acceleration produced because of friction
f=MN => Mmg
a = Mg
Option 1)
This is incorrect option
Option 2)
This is incorrect option
Option 3)
This is correct option
Option 4)
This is incorrect option
View Full Answer(1)When a constant force is applied to a body, it moves with uniform:
Acceleration
Velocity
Speed
Momentum
As we discussed in
Newton's 2nd Law -
Therefore
- wherein
in C.G.S & S.I
when a constant force is applied on a body, the body's accelerated with uniform acceleration.
Option 1)
Acceleration
Correct
Option 2)
Velocity
Incorrect
Option 3)
Speed
Incorrect
Option 4)
Momentum
Incorrect
View Full Answer(1)What is the mechanical advantage of single fixed pulley?
1
2
0.5
4
As we discussed in
Motion of connected blocks over pulley -
Equation of motion for
Equation of Motion for
- wherein
Option 1)
1
Correct
Option 2)
2
Incorrect
Option 3)
0.5
Incorrect
Option 4)
4
Incorrect
View Full Answer(1)Two bodies of masses 4kg and 5kg are acted upon by the same force. If the acceleration of lighter body is , acceleration of heavier body is:
As we discussed in
When 2 Blocks are in Contact -
- wherein
when same force applied on both bodies tried together
Option 1)
Incorrect
Option 2)
Incorrect
Option 3)
Incorrect
Option 4)
Correct
View Full Answer(1)Two blocks of masses 5kg and 10kg are connected to a pulley as shown in fig. What will be the acceleration if the pulley is set free?
g
g/2
g/3
g/4
(M1-M2)G/M1+M2. =10-5×g/10+5=5g/15=g/3
Option 3
View Full Answer(2)Three blocks are connected as shown on a horizontal frictionless surface , if will be?
18N
9N
3.375N
1.75 N
Answer 2
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Please,please help me - Newtons Laws of Motion - JEE Main
Help me solve this - Laws of motion - BITSAT
I have a doubt, kindly clarify. - Laws of motion - BITSAT
Please,please help me When a constant force is applied to a body, it moves with uniform:
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