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A metal (A) on heating in nitrogen gas gives compound B. B on treatment with $H_{2}O$ gives a colourless gas which when passed through $CuSO_{4}$ solution gives a dark blue-violet coloured solution. A and B respectively, are :
Option: 1 $Na$ and $Na_{3}N$
Option: 2 $Mg$ and $Mg_{3}N_{2}$
Option: 3 $Mg$ and $Mg(NO_{3})_{2}$
Option: 4 $Na$ and $NaNO_{3}$

Magnesium reacts with air to form its nitride. The nitride upon hydrolysis yields ammonia which gives a deep blue color solution with $CuSO_4$

$3Mg+N_{2}\rightarrow \underset{(B)}{Mg_{3}N_{2}}\overset{H_{2}O}{\rightarrow}Mg(OH)_{2}+NH_{3}$

$CuSO_4 + 2NH_3 \longrightarrow [Cu(NH_3)_2]SO_4$

Therefore, Option(2) is correct.

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vishal kumar

In the following reactions, products (A) and (B) respectively are: $NaOH + Cl_{2}\rightarrow A +NaCl+ side\ product$ (hot and conc.) $Ca(OH)_{2}+Cl_{2}\rightarrow B + CaCl_2+ side\ product$ (dry)
Option: 1 $NaClO_{3}\ and\ Ca(ClO_{3})_{2}$
Option: 2 $NaOCl\ and\ Ca(OCl)_{2}$
Option: 3 $NaClO_{_{3}}\ and\ Ca(OCl)_{2}$
Option: 4 $NaOCl\ and\ Ca(ClO_{3})_{2}$

As we have learnt,

Chlorine reacts with $NaOH$ and $Ca(OH)_2$ and undergoes disproportionation. The products depend upon the concentration of the base and also the temperature.

The reactions are given as

$2Na(OH) + 3 Cl_2 \longrightarrow NaClO_3 +5 NaCl + 3 H_2O$

(Hot and Conc.)

$2 Ca(OH)_2 + 2 Cl_2 \longrightarrow Ca(OCl)_2 + CaCl_2 + 2 H_2O$

(Dry)

Therefore, Option(4) is correct.

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Kuldeep Maurya

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Among the sulphate of alkaline earth metals the solubilities of $BeSO_{4}$ and $MgSO_{4}$ in water, respectively, are -
Option: 1 high and poor
Option: 2 poor and poor
Option: 3 high and high
Option: 4 poor and high

$BeSO_{4}$ and $MgSO_{4}$ are readily soluble in water. Thus, the solubility of both these sulphates is high in water.

Therefore, Option(3) is correct.

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Kuldeep Maurya

Match the following compounds (Column-I) with their uses (Column-II):

S.No Column-I S.No Column-II

(I) $Ca(OH)_{2}$ (A) casts of statues

(II) $NaCl$ (B) White wash

(III) $CaSO_{4}.\frac{1}{2}H_{2}O$ (C) antacid

(IV) $CaCO_{3}$ (D) washing soda preparation

Option: 1 (I) - (D), (II) - (A), (III) - (C), (IV) -(B)
Option: 2 (I) - (B), (II) - (D), (III) - (A), (IV) -(C)
Option: 3 (I) - (B), (II) - (C), (III) - (D), (IV) -(A)
Option: 4 (I) - (C), (II) - (D), (III) - (B), (IV) -(A)

Compounds and their uses-

Therefore, the correct option is (2).

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Kuldeep Maurya

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One combination of Li, Na and K in excess of air, the major oxides formed, respectively are:
Option: 1 $\mathrm{Li}_{2} \mathrm{O}_{2}, \mathrm{Na}_{2} \mathrm{O}_{2} \text { and } \mathrm{K}_{2} \mathrm{O}_{2}$
Option: 2 $\mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}_{2} \text { and } \mathrm{KO}_{2}$
Option: 3 $\mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O} \text { and } \mathrm{K}_{2} \mathrm{O}_{2}$
Option: 4 $\mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}_{2} \text { and } \mathrm{K}_{2} \mathrm{O}$

The formed oxides will be -

$\mathrm{Li}+\mathrm{O}_{2}\textup{ (excess)} \rightarrow \mathrm{Li}_{2} \mathrm{O} \text { (Major oxides) }$ $\mathrm{Na}+\mathrm{O}_{2}\textup{ (excess)} \rightarrow \mathrm{Na}_{2} \mathrm{O}_2 \text { (Major oxides) }$ $\mathrm{K}+\mathrm{O}_{2}\textup{ (excess)} \rightarrow \mathrm{K} \mathrm{O}_2 \text { (Major oxides) }$

Therefore, the correct option is (2).

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Kuldeep Maurya

An alkaline earth metal 'M' readily forms water soluble sulphate and water insoluble hydroxide. Its oxide MO is very stable to heat and does not have rock-salt structure M is:
Option: 1 Sr
Option: 2 Ca
Option: 3 Mg
Option: 4 Be

M is "Be" alkaline earth metal.

Be readily forms water-soluble sulphate BaSO₄

Be(OH)₂ is water-insoluble hydroxide.

BeO is very stable to heat and does not have a rock-salt structure.

Therefore, the correct option is (4).

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Kuldeep Maurya

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Among the statements (I–IV), the correct ones are:
(I) Be has smaller atomic radius compared to Mg.
(II)Be has higher ionization enthalpy than Al.
(III) Charge/radius ratio of Be is greater than that of Al.
(IV) Both Be and Al form mainly covalent compounds.
Option: 1 (I), (II) and (IV)
Option: 2 (I), (III) and (IV)
Option: 3 (II), (III) and (IV)
Option: 4 (I), (II) and (III)

(I) Be has a smaller atomic radius compared to Mg, in a group atomic radius increases.
(II) Be has higher ionization enthalpy than Al due to fully filled s-block orbital of Be.
(III) Charge/radius ratio of Be is greater than that of Al, due to Be being small.
(IV) Only Al form mainly covalent compounds, Be forms ionic compounds.

(I), (II), and (IV) are correct.

Therefore, Option 1 is correct.

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Posted by

Kuldeep Maurya

Match List - I with List - II:

List - I List - II

(a) Ca(OCl)₂ (i) Antacid

(b) CaSO₄.1/2 H₂O (ii) Cement

(c) CaO (iii) Bleach

(d) CaCO₃ (iv) Plaster of Paris

Choose the most appropriate answer from the options given below :

Option: 1 (a) - (iii), (b) -(iv), (c) - (ii), (d) -(i)
Option: 2 (a) - (iii), (b) -(ii), (c) - (i), (d) -(iv)
Option: 3 (a) - (i), (b) -(iv), (c) - (iii), (d) -(ii)
Option: 4 (a) - (iii), (b) -(ii), (c) - (iv), (d) -(i)

We know these facts.

Ca(OCl)₂ is Bleach

CaSO₄.1/2 H₂O is Plaster of Paris.

CaCO₃ is used as an antacid.

CaO is the major component of cement.

The correct matching : (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)

Therefore, the Correct option is (1)

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Kuldeep Maurya

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The correct order of conductivity of ions in water is :

Option: 1 $K^{+}>Na^{+}>Cs^{+}>Rb^{+}$
Option: 2 $Rb^{+}>Na^{+}>K^{+}>Li^{+}$
Option: 3 $Cs^{+}>Rb^{+}>K^{+}>Na^{+}$
Option: 4 $Na^{+}>K^{+}>Rb^{+}>Cs^{+}$

$\mathrm{Cs}_{\mathrm{aq}}^{+}$ has lower hydrated radius so its electrical conductivity is higher.

Therefore, the correct option is (3)

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Kuldeep Maurya

Given below are two statements : Statement I : Both CaCl₂.6H₂O and MgCl₂.8H₂O undergo dehydrationon heating. Statement II : BeO is amphoteric whereas the oxides of other elements in the same group are acidic. In the light of the above statements, choose the correct answer from the options given below :
Option: 1 Statement I is false but statement II is true
Option: 2 Both statement I and Statement II are false
Option: 3 Statement I is true but statement II is false
Option: 4 Both statement I and Statement II are true

$\text { (a) } \mathrm{CaCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O} \stackrel{\Delta}{\longrightarrow} \underset{\text { (Anhydrous) }}{\mathrm{CaCl}_{2}}+6 \mathrm{H}_{2} \mathrm{O}$

$\text { (b) } \mathrm{MgCl}_{2} .8 \mathrm{H}_{2} \mathrm{O} \stackrel{\Delta}{\longrightarrow} \mathrm{MgO}+2 \mathrm{HCl}+6 \mathrm{H}_{2} \mathrm{O}$

The dehydration of hydrated chloride of calcium can be achieved. The corresponding hydrated chloride of magnesium on heating suffer hydrolysis.

$\text { (c) } \mathrm{BeO} \rightarrow \text { Amphoteric }$

MgO, CaO, SrO, BaO All are basic oxides.

So, Both Statement I and Statement II are false

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Kuldeep Maurya

JEE Main high-scoring chapters and topics

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S.No	Column-I	S.No	Column-II
(I)	$Ca(OH)_{2}$	(A)	casts of statues
(II)	$NaCl$	(B)	White wash
(III)	$CaSO_{4}.\frac{1}{2}H_{2}O$	(C)	antacid
(IV)	$CaCO_{3}$	(D)	washing soda preparation

List - I	List - II
(a) Ca(OCl)₂	(i) Antacid
(b) CaSO₄.1/2 H₂O	(ii) Cement
(c) CaO	(iii) Bleach
(d) CaCO₃	(iv) Plaster of Paris

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Get Answers to all your Questions

All Questions

A metal (A) on heating in nitrogen gas gives compound B. B on treatment with gives a colourless gas which when passed through solution gives a dark blue-violet coloured solution. A and B respectively, are : Option: 1 and Option: 2 and Option: 3 and Option: 4 and

Posted by

vishal kumar

In the following reactions, products (A) and (B) respectively are: (hot and conc.) (dry) Option: 1 Option: 2 Option: 3 Option: 4

Posted by

Kuldeep Maurya

Crack CUET with india's "Best Teachers"

Among the sulphate of alkaline earth metals the solubilities of and in water, respectively, are - Option: 1 high and poor Option: 2 poor and poor Option: 3 high and high Option: 4 poor and high

Posted by

Kuldeep Maurya

Posted by

Kuldeep Maurya

JEE Main high-scoring chapters and topics

One combination of Li, Na and K in excess of air, the major oxides formed, respectively are:Option: 1 Option: 2 Option: 3 Option: 4

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Among the sulphate of alkaline earth metals the solubilities of $BeSO_{4}$ and $MgSO_{4}$ in water, respectively, are -
Option: 1 high and poor
Option: 2 poor and poor
Option: 3 high and high
Option: 4 poor and high

An alkaline earth metal 'M' readily forms water soluble sulphate and water insoluble hydroxide. Its oxide MO is very stable to heat and does not have rock-salt structure M is:
Option: 1 Sr
Option: 2 Ca
Option: 3 Mg
Option: 4 Be

The correct order of conductivity of ions in water is :

Option: 1 $K^{+}>Na^{+}>Cs^{+}>Rb^{+}$
Option: 2 $Rb^{+}>Na^{+}>K^{+}>Li^{+}$
Option: 3 $Cs^{+}>Rb^{+}>K^{+}>Na^{+}$
Option: 4 $Na^{+}>K^{+}>Rb^{+}>Cs^{+}$