A simple pendulum has a time period  $T_{1}$  when on the earth's surface and $T_{2}$  when taken to a height R above the earth's surface, where R is the radius of the earth. The value of  $T_{2}/T_{1}$  is  A)    1         B)  √2C)   4         D)   2

@ vishal

T=$T=2\pi \sqrt{\frac{l}{g}}$

g is inversly proportional to $(R+h)^2$ …..........h is height above the earth’s  surface

therefore T is proportional to R+h

$\frac{T_{2}}{T_{1}}=\frac{R+h}{R}$       ............ putting h=R

We get $\frac{T_{2}}{T_{1}}=\frac{R+R}{R}=2$

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