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10 identical cell each of emf 4V and internal resistance 10\Omega are connected in parallel across external resistance of  1\Omega then current (in A) through each cell is

Option: 1

0.2


Option: 2

0.4


Option: 3

2


Option: 4

4


Answers (1)

best_answer

As we learnt

Current from each cell -

i'= \frac{i}{n}

-

Total Current

 

 I=\frac{E}{R+\frac{r}{n}}=\frac{4V}{1+\frac{10}{10}}= 2A

Current through each cell is 

\frac{i}{n}= 0.2A

Posted by

jitender.kumar

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