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  • 12 identical cells each with emf 4V and internal resistance 1 are connected in series. The power dissipated (in W ) through

12 identical cells each with emf 4V and internal resistance 1 are connected in series. The power dissipated (in W ) through an external resistance of  8 connected with this system is

Option: 1

46


Option: 2

42


Option: 3

32


Option: 4

54


Answers (1)

best_answer

As we learnt

 

Power dissipiated in the external circuit -

 

(\frac{nE}{R+nr})^{2}\cdot R

-

 

 Current through the external resistor is 

I=\frac{nE}{R+nr}=\frac{48}{8+12}=2.4A

The power dissipated in the external circuit -

= I^{2}\cdot R= \left ( 2.4 \right )^{2}*8=46W

Posted by

HARSH KANKARIA

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