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6 identical cells with emf 3V and internal resistance 1 $\Omega$ are connected in a row and 3 such rows are connected together in parallel with an external resistance of 3 $\Omega$ . Then current through each cell is
Option: 1
$\frac{4}{5}A$

Option: 2
$\frac{6}{7}A$

Option: 3
$\frac{6}{5}A$

Option: 4
$\frac{4}{7}A$

Answers (1)

best_answer

As we learnt

Current from each cell -

$i'= \frac{i}{m}$

-

$i=\frac{mnE}{mR+nr}$

m=3,n=6, E=3V

$R=3\Omega\: \: \: \: r=1\Omega$

$i=\frac{18*3}{9+6}=\frac{18}{5}A$

$\therefore$ Current through each cell

$=\frac{i}{m}=\frac{18}{5*3}= \frac{6}{5}A$

Posted by

Rakesh

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