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7 identical cell each of emf 1.5V and internal resistance 1.75 are connected in parallel and then connected across external resistance of 3.75 then potential drop (in volts) across the external resistor is
Option: 1
1.4

Option: 2
1.2

Option: 3
1.5

Option: 4
1.8

Answers (1)

best_answer

As we learnt

Potential difference across external resistance -

$V=iR$

-

$=\frac{E}{R+\frac{r}{n}}.R= \frac{1.5*3.75}{3.75+\frac{1.75}{7}}= 1.4V$

Posted by

seema garhwal

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