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15486380425468794424014177925083.jpg Equal volumes of 0.5M of HCL ,0.25M of NaOH and 0.75M of NaCl are mixed. The molarity of NaCl solution is- (A) 0.75M (B) 1/3M(C) 0.50M (C) 2.00M

Answers (1)

the molarity of NaCl in the solution should be 1/3 i.e option B should be correct.0.25 M NaOH will act as a limiting reagent for the reaction between HCl and NaOH.

Assume volume of each before mixing is 1L

                                HCl      +    NaOH →NaCl + H2O

before reaction        0.50*1         0.25*1    0.75*1    --

 after reaction           0.25             0         0.75+0.25

 

total volume after mixing = 1+1+1 =3L

Now NaCl =1 mol in 3L 

so molarity is 1/3

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Ankit

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