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  • A 10μF capacitor is charged to a potential difference of 50V and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes 20 volts. The capacitance of the second capacitor is  

A 10μF capacitor is charged to a potential difference of 50V and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes 20 volts. The capacitance of the second capacitor is  
Option: 1 10μF
Option: 2 30μF
Option: 3  20μF  
Option: 4 15μF

Answers (1)

best_answer

\\ \text{First case:}\\ Q=10 \times 50=500 \mu C \\ \text{Second case:} \\ 500=(C+10) \times 20 \\ \Rightarrow C=15 \mu F

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avinash.dongre

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