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A and B are two sources generating sound waves. A listener is situated at C. The frequency of the source at A is 500 Hz. A,now, moves towards C with a speed 4m/s. The number of beats heard at C is 6. when A moves away from C with speed 4m/s, the number of beats heard at C is 18. The speed of sound is 340m/s. The frequency of the source at B is :

Option: 1

500Hz


Option: 2

506Hz


Option: 3

512Hz


Option: 4

494Hz


Answers (1)

best_answer

Let frequency of source B=f

In 1st case,

\frac{f_{o} V}{V-4}-f=6

In 2nd case,

f-\frac{f_{0} V}{V+4}=100

 

Solving (i) and (ii), we get

            f=512 Hz

Posted by

sudhir.kumar

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