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  • A ball of mass 1 g and charge C moves from a point A. where potential is 600 volt to the point B where

A ball of mass 1 g and charge 10^{-8} C moves from a point A. where potential is 600 volt to the point B where potential is zero. Velocity of the ball at the point B is 20 cm/s. The velocity of the ball at the point A will be 

Option: 1

22.8 cm/s


Option: 2

228 cm/s


Option: 3

16.8 m/s


Option: 4

168 m/s


Answers (1)

 

By using  

\\*\frac{1}{2}m(v^2_1 - v^2_2) = QV \\*\frac{1}{2}\times 10^{-3} (v_1^2 - (0.2)^2) = 10^{-8}(600 - 0) \Rightarrow v_1 = 22.8 cm/s

Posted by

Kshitij

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