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A block A of mass 2 kg rests on another block B of mass 8 kg which rests on a horizontal floor. The coefficient of friction between A and B is 0.2, while that between B and floor is 0.5. When a horizontal force of 25 N is applied on the block B, the force of friction between A and B is

Option: 1

0
 


Option: 2

3.9 N


Option: 3

5.0 N

 


Option: 4

50 N


Answers (1)

best_answer

 

Limiting friction between the block B and the surface

F_{BS}=\mu _{BS}R=0.5(m+M)g=0.5(2+8)10=50 N

but the applied force is 25 N so the lower block will not move i.e. there is no pseudo force on upper block A. Hence there will be no force of friction between A and B.

 

Posted by

Ritika Harsh

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