A block of mass 1kg is at rest on a rough horizontal surface having coefficient of static friction 0.2 and kinetic friction 0.15, find the friction force (in Newtons) if horizontal force of 2.5N is applied on block -
(g=9.8m/s2)
1.47
2.5
1.7
2.3
As we learn
Friction -
Opposing Force which is parallel to the surface and opposite to direction of Relative Motion.
- wherein
Direction of friction is always opposite the direction of Relative Motion.
fext.=2.5N
Fl = 0.2 * 1 * 9.8 = 1.96N
body will be in moving condition
friction force,
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