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  • A block of mass 5 Kg is at rest on a horizontal smooth surface. A constant force  F = 10 N is applied horizontally on the block then the displacement (in meters) of the block after 2 sec

A block of mass 5 Kg is at rest on a horizontal smooth surface. A constant force  F = 10 N is applied horizontally on the block then the displacement (in meters) of the block after 2 sec will be

Option: 1

4


Option: 2

10


Option: 3

8


Option: 4

5


Answers (1)

best_answer

Solution : 

\\ \text{Given :} \\ \text{Mass,(m)}=5 \ kg \\ \text{Initial velocity,(u)}=0 \\ \text{Horizontal force,(F)}= 10 N \\ \text{Time,(t)}= 2s \\ \text{Displacement,(s)}=? \\ \text{Free body diagram of given block : }

F=ma \\ \\ \therefore a=\frac{F}{m} =\frac{10}{5}=2 \ m/s^{2}

\\ \text{Now,applying 2nd equation of motion-}

\\ s=ut+\frac{1}{2}at^2\\ \\ \ \ s=0+\frac{1}{2}\times2\times2^{2}\\ \\ \Rightarrow s=4m

 

Posted by

Divya Prakash Singh

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