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  • A block of mass 5Kg is suspended by a massless string at the roof of a lift moving upwards with constant velocity 10 m/s  The tension M (in newtons) on the string is (<img alt="

A block of mass 5Kg is suspended by a massless string at the roof of a lift moving upwards with constant velocity 10 m/s 

The tension M (in newtons) on the string is (g = 10 m/ s^ 2)

Option: 1

50


Option: 2

30


Option: 3

10


Option: 4

40


Answers (1)

best_answer

As we have learned

Lift is moving upward or down with constant Velocity -

v=const,\:a=0


R=mg

- wherein

Apparent weight  = Actual weight

 

 

Moving with constant velocity so 

a = 0 

T- mg = ma 

T = mg 

5* 10 = 50 N 

 

Posted by

Irshad Anwar

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