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  • A bob is hanging over a pulley inside a car through a string  . The second end of the string is in the hand of a person standing in the car . The car is moving with constant acceleration '

A bob is hanging over a pulley inside a car through a string  . The second end of the string is in the hand of a person standing in the car . The car is moving with constant acceleration 'a' directed horizontally as shown in figure . Other end of the string is pulled with constant acceleration ' a ' vertically downward.

            The tension in the string is equal to :

Option: 1

m\sqrt{g^{2}+a^{2}}


Option: 2

m\sqrt{g^{2}+a^{2}}-ma


Option: 3

m\sqrt{g^{2}+a^{2}}+ma


Option: 4

m\left (g+a \right )


Answers (1)

best_answer

As we learned 

Newton's 2nd Law -

    F=ma

 Apply the concept of pseudo force as shown in the below figure

 

\begin{array}{l}{\text { Applying Newton's law perpendicular to string }} \\ {m g \sin \theta=m a \cos \theta} \\ {\Rightarrow \tan \theta=\frac{a}{g}}\end{array}

 \begin{array}{l}{\text { Applying Newton's law along string, }} \\ {T-m g \cos \theta-m a \sin \theta=m a} \\ {\Rightarrow T=m \sqrt{g^{2}+a^{2}}+m a}\end{array}

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Pankaj

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