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  • A body is moving with speed 12m/s and coeficient at friction between the ground and the body is 0.4.The distance travelled by the body (in meters)  before coming to rest is.<div class='qna

A body is moving with speed 12m/s and coeficient at friction between the ground and the body is 0.4.The distance travelled by the body (in meters)  before coming to rest is.

Option: 1

18


Option: 2

10


Option: 3

15


Option: 4

20


Answers (1)

best_answer

As we learn

Stopping of block due to friction -

On horizontal road

F=ma = \mu R

ma = \mu mg

a = \mu g

V^{2}=u^{2}-2as

S = \frac{u^{2}}{2\mu g}=\frac{P^{2}}{2\mu m^{2}g}

- wherein

a = acceleration 

\mu= coefficient of friction

S = distance travelled

g = gravity

V = finally velociy

u = Initial velocity

P = momentum

 

 

 f = \mu mg

due to retardation

\mu mg=ma\Rightarrow a=\mu g =0.4*10=4m/s^{2}

now for V=0

V^{2}=u ^{2}-2as\Rightarrow 0=u ^{2}-2as

S=\frac{u ^{2}}{2\times a}\Rightarrow \frac{12*12}{2*4}=18m

 

 

Posted by

Kuldeep Maurya

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